How can I find the thermal output power of my PT-50-CG or other Luminus Device?

Most of the electricity in an LED becomes heat rather than light (about 70% heat and 30% light).^[1]

One can calculate the thermal power of a device to be derived from the following equation.

Total Electrical Power = Power_Optical + Power_Thermal

If we take the PT-50 devices for example, the Electrical & Optical Characteristics are shown in the table below.

Example 1) PT-50-B @ Typical Conditions (Test drive current = 12.5A, Typical Voltage = 3V)

Total Electrical Power = 12.5A * 3V = 37W

Power_Optical = 14W

^{therefore : Total Electrical Power - Power_Optical = Power_Thermal}

Power_Thermal = 37W - 14W = 23W

Example 2) PT-50-CG @ Typical Conditions (Test drive current = 12.5A, Typical Voltage = 3V)

In regards to the PT-50-CG, this is a Blue die utilizing a phosphor to convert the color to green. Utilizing the 14W for the Power_Optical for the CG would be correct in this instance. The solution to this example is the same as Example 1

Example 3) PT-50-B @ Maximum Current Conditions (Drive Current = 20A, Voltage = ~3V)

According to the datasheet graph below, at 20A we have a relative flux increase to 140%. Therefore at this current the radiometric power would be 140% of 14W = 19.6W

Total Electrical Power = 20A * 3V = 60W

Power_Optical = 19.6W

^{therefore : Total Electrical Power - Power_Optical = Power_Thermal}

Power_Thermal = 60W - 19.6W = 40.4W

^{[1] https://www.ledsmagazine.com/leds-ssl-design/thermal/article/16696536/fact-or-fiction-leds-dont-produce-heat}

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